04-04-2017
Chemistry

contestada

How many grams of Lead(II) nitrate are present in 150.0 mL of an Lead(II) nitrate solution that is 0.07268 M?

Respuesta :

AnonymousA7 AnonymousA7

04-04-2017

hey...
Use the molarity formula
M=moles/L and then convert to grams

0.07268*0.15=moles
0.010902 mol
Pb(NO3)2
1 mole=331.22g
0.010902 moles=

3.61 g

Answer Link

Otras preguntas

One aspect of the Soviet unions foreign policy following world war 2 was to

In a point-by-point comparison, you

Which statement describes a strong U.S. dollar?

In this cover letter text, what most needs to be revised?

4x-6>22 explain or prove if 5 or 8 is a solution to the inequality

The replacer parameter of the stringify method accepts a/an ______________ or an array.

Describe an object that is transparent. What quality makes it transparent?

Mr. Granville needs some plywood that is about three over four-inch thick. Which plywood is closest to three over four-inch thick? A Image of plywood A D

If Harriet was born in 1822, how old was she when she made her first and last rescue?

Why is it important to protect Earth water, land, and air resource?