ZaelaU86484 ZaelaU86484
  • 03-11-2022
  • Chemistry
contestada

Problem set3. What is the [OH-] of a solution that has a pH of 2?

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AlonniJ190357 AlonniJ190357
  • 03-11-2022

We have a solution that pH = 2

We can use this relation which says:

pH + pOH = 14

If we clear pOH from here:

pOH = 14 - pH = 14 - 2 = 12

So, pOH = 12 and pOH could be calculated as:

pOH = - log [OH-] => we clear [OH-] from this,

10^(-pOH) = [OH-] => 10^(-12) = [OH-] => 1x10^-11 mol/L = [OH-]

(mol/L is generally the unit for [OH-])

Answer: [OH-] = 1x10^-11 mol/L

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