abhiyan2067
abhiyan2067 abhiyan2067
  • 04-07-2022
  • Physics
contestada

The Volume Of a Body weighing is 1200 kg is 250000 [tex]cm^{3}[/tex] Find ITs density.


Write With Formula

Respuesta :

Аноним Аноним
  • 04-07-2022

Answer:

[tex]\boxed {Density = 4800 kg/m^{3}}[/tex]

Explanation:

Formula :

[tex]\boxed {Density = \frac{Mass (kg)}{Volume (m^{3})}}[/tex]

Convert volume into standard unit :

⇒ 250000 cm³ × 10⁻⁶

⇒ 0.25 × 10⁶ × 10⁻⁶

⇒ 0.25 m³

Solve for density :

⇒ Density = 1200 kg / 0.25 m³

⇒ Density = 1200 × 4 kg/m³

⇒ Density = 4800 kg/m³

Answer Link

Otras preguntas

1/8 x 1/8 as a exponet
Wht was euphemism for death in Jonas Community?​
Divide. (5/6)÷(−2/3) For brainliest if answer is correct −5/4 ​−5/9​ 5/9 ​5/4​
in the new union of soviet socialist republics, all of the power was contracted in the hands of a small ruling group called ... Politburo central commitee pet
-(1/2)is the same as
I don't get it PLEASE HELP!!!
33. import pandas as pd import numpy as np kvs = [10,11,12] jtp = pd.Series (kvs) print(itp) #What will be output of prog? A) 0 10 111 2 12 B) [10,11,12] C)-1 1
what is one of the main points of horace miner’s article ""body ritual among the nacirema""?
PLEASE HELP ME ASAP 15 POINTS
Which description represents the expression 4−x/3? A. 4 minus the quotient of a number and 3 B. 4 times the quotient of a number and 3 C. 4 added to the product