belld70 belld70

01-02-2021
Physics

contestada

What is the independent variable?

Diameter
Circumference

Respuesta :

elyseburney elyseburney

01-02-2021

Answer:

Diameter

Explanation:

I know that circumference is dependent, so diameter has to be independent

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[tex](\frac{1}{16} )^{3-2a} =64^{-a}[/tex] (1/16)^(3-2a)=64^(-a)