Answer:
Mass  = 121 g
Explanation:
Given data:
Mass in gram of COâ‚‚ = ?
Volume = 61.8 L
Pressure = standard = 1 atm
Temperature = 273.15 K
Solution:
Formula:
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K Â
T = temperature in kelvin
1 atm Ă— 61.8 L = n Ă—0.0821 atm.L/ mol.K Â Ă— 273.15 k
61.8 L.atm = 22.42 atm.L/ mol Ă— n
n = 61.8 L.atm /22.42 atm.L/ mol
n = 2.76 mol
Mass in gram:
Mass = Â number of moles Ă— molar mass
Mass = 2.76 mol Ă— 44 g/mol
Mass  = 121 g