gabby15222 gabby15222

01-11-2020
Mathematics

contestada

Find all the solution of the equation in the interval [0,2pi] 2sin2x =0

Respuesta :

naenaecvsh naenaecvsh

01-11-2020

Answer:

π

8

and

9

π

8

Step-by-step explanation:2

sin

(

2

x

)

−

√

2

=

0

sin

2

x

=

√

2

2

2

x

=

sin

−

1

(

sin

2

x

)

=

sin

−

1

(

√

2

2

)

=

π

4

2

x

=

π

4

⇒

x

=

π

8

−

π

8

=

π

+

π

8

=

9

π

8

For:

888

0

<

x

≤

π

π

8

and

9

π

8

Answer Link

gufeliz1965 gufeliz1965

01-11-2020

See attachment for math work and answer.

Ver imagen gufeliz1965

Answer Link

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