mgeorgiadis16 mgeorgiadis16
  • 02-10-2020
  • Mathematics
contestada

The perimeter of a standard basketball court is 288 feet. The length is 44 feet longer than the width. What are the dimensions of the court?

Respuesta :

potato1dani16 potato1dani16
  • 02-10-2020

Answer:

Perimeter = 2l + 2w    //l=length, w=width

l = 44 + w

Now substitute 44 + w in place of l in the above equation and you have

2(44 + w) + 2w = 288

=> 88 + 2w + 2w = 288

=> 88 + 4w = 288

=> 4w = 200

=> w = 50 and l = 44 + 50 = 94

2*94 + 2*50=288

Step-by-step explanation:

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