jashonsullivan jashonsullivan
  • 04-04-2020
  • Mathematics
contestada

What are the real or imaginary solutions of 2x+7X? = 15x7
A. 0, , -5
B. 0,-1,5
C. 15
D. 0, -3,5

Respuesta :

wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 04-04-2020

Answer:

x=0  x=(3/5)^1/6

Step-by-step explanation:

2x+7X? = 15x7

Combine like terms

9x = 15 x^7

Subtract 9x from each side

9x-9x = 15x^7 -9x

0 = 15x^7 -9x

Factor out 3x

0 =3x(5x^6 -3)

Using the zero product property

3x= 0   5x^6 -3 =0

x=0      5x^6 =3

              x^6 = 3/5

             Take the sixth root

             x = (3/5)^1/6

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