bri979235 bri979235
  • 03-09-2019
  • Mathematics
contestada

Write the equation of a line containing the point (-4, 6) and parallel to 3x - 2y =8.

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lala2944 lala2944
  • 03-09-2019
3x -2y=8
Y= 3/2 x- 4
Hence slope is 3/2
The line d (for example) is parallel to this line the slope of d = slope of this line = 3\2
Then equation of d : y =3/2 x - b
The point (-4,6) belongs to d
Y - 6 = 3/2 (x +4)
Y= 3/2 x + 6 +6
Y= 3/2x +12


Then the equation is : Y= 3/2x +12
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mathwiz33 mathwiz33
  • 03-09-2019
The answer is 3x + 2y - 8 += 0
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