ks2021 ks2021
  • 02-12-2018
  • Mathematics
contestada

PLEASE HURRY

9x^2 + 64 = 0

I NEED THE WORK SHOWN IN ORDER TO GET CREDIT

Respuesta :

jimrgrant1 jimrgrant1
  • 02-12-2018

Answer:

x = ± [tex]\frac{8}{3}[/tex] i

Step-by-step explanation:

subtract 64 from both sides

9x² = - 64 ( divide both sides by 9 )

x² = - [tex]\frac{64}{9}[/tex] ( take the square root of both sides )

x = ± [tex]\sqrt{-64/9}[/tex] = ± [tex]\frac{8}{3}[/tex] i


Answer Link
Аноним Аноним
  • 02-12-2018

Answer:

see below

Step-by-step explanation:

9x^2 + 64 = 0

9x^2 = -64

x^2 = -64 / 9  

Taking square roots of both sides:-

x = +/-  (-8/3)

x = -8i/3 , 8i/3

Answer Link

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