hannatrinh
hannatrinh hannatrinh
  • 03-10-2018
  • Mathematics
contestada

Factor the expression over the complex numbers.

x^2+52

Respuesta :

Kristiania Kristiania
  • 12-10-2018

Here we are given the expression:

[tex]x^{2}+52[/tex]

Now let us equate it to zero to find x first,

[tex]x^{2}+52=0[/tex]

Now subtracting 52 from the other side,

[tex]x^{2}=-52[/tex]

taking square root on both sides,

So we will get two values of x as ,

[tex]x=+2\sqrt{-13}[/tex]

[tex]x=-2\sqrt{-13}[/tex]

Now we can write square root -1 as i,

So our factors become,

[tex]x=+2i\sqrt{13}[/tex]

[tex]x=-2i\sqrt{13}[/tex]

Answer:

The final factored form becomes,

[tex](x+2i\sqrt{13})(x-2i\sqrt{13})[/tex]


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