prodighyk4086 prodighyk4086
  • 04-09-2018
  • Chemistry
contestada

If a large marshmallow has a volume of 2.25 in3 and density of 0.242 g/cm3, how much would it weigh in grams? 1 in3=16.39 cm3.

Respuesta :

Chlidonias
Chlidonias Chlidonias
  • 13-09-2018

Given the volume of marshmallow = [tex]2.25 in^{3}[/tex]

Density of marshmallow = [tex]0.242\frac{g}{cm^{3} }[/tex]

Converting volume from [tex]in^{3} to cm^{3}[/tex]:

[tex]2.25 in^{3} * \frac{16.39 cm^{3} }{1 in^{3} }  =36.8775 cm^{3}[/tex]

Calculating the mass from volume and density:

[tex]36.8775 cm^{3} * \frac{0.242 g}{cm^{3} } = 8.92 g[/tex]

Therefore, the mass of marshmallow is 8.92 g

Answer Link

Otras preguntas

Can someone tell me a poem in sapnish
Question 1 25 pts What is the total surface area of the following rectangular prism shown below? 3 in 10 in 4 in
What is the length of MN
the volume of this cone is 540pi. Work out the height, h, of the cone
Plss answer the 3 questions and read the text.ITS REALLY FUN!!!.Earn 60 points by answering correctly
I need help finding the answer.
What is not a power given to congress in the constitution
calculate the area and volume of the ball of radius: a) r = 4 cm; b) √3 cm
Which of the following is the most important person at helping the President run the White House?A. No one, the President does everything by his or herself.B. S
The steps below show the incomplete solution to find the value of m for the equation 4m - 2m + 4 = -1 + 13: Step 1: 4m - 2m + 4 = -1 + 13 Step 2: 4m - 2m + 4 =